1. Solve the system using substitution (1 point)x + y = 8y = 3x(A). (4, 12)(B). (2, 6)(C). (1/2, 3/2)(D). (-4, -12) 2. Solve the system using substitution (1 point) 2x + 2y = 38y = x + 3 (A). (8, 11)(B). (4, 7)(C). (35/4, 47/4) (D). (-4, -7)3. Solve the system using substitution (1 point)y = 8 - x 7 = 2 - y (A). (5, 13)(B). (13, -5)(C). (3, 5)(D). (21, -13)4. Solve the system using substitution (1 point)3x + 2y = 231/2x - 4 = y(A). (9, -2)(B). (27/4, -5/8)(C). (31/4, -1/8)(D). (3/2, -13/4)5. Solve the system using substitution (1 point)y - 2x = 33x - 2y = 5(A). (-1/2, 2)(B). (2, 7)(C). (-8, -13)(D). (-11, -19)Unit 7 Lesson 2, Solving Systems Using Substitution. If you completed this Algebra lesson yet please give me the rest of the answers!! Thanks!! :)
Accepted Solution
A:
I'll do the first two so that you can try and practice them on your own.
1.
y = 3x, let's input that into the other equation.
x + 3x = 8 4x = 8 Divide both sides by 4. x = 2
y = 3(2) y = 6
(2, 6)
2.
y = x + 3, let's input that into the other equation.
2x + 2(x + 3) = 38 2x + 2x + 6 = 38 Subtract 6 from both sides. 4x = 32 Divide both sides by 4. x = 8