5 months ago

42/6+2+45/5(32/8+32)+2

Accepted Solution

Multiply the numbers

$\frac{ 42 }{ 6 }+2+\frac{ 45 }{ 5 } \times \left( \frac{ 32 }{ 8 }+6 \right)+2$

Cancel out the common factor $8$

$\frac{ 42 }{ 6 }+2+\frac{ 45 }{ 5 } \times \left( 4+6 \right)+2$

Cancel out the common factor $5$

$\frac{ 42 }{ 6 }+2+9\left( 4+6 \right)+2$

Cancel out the common factor $6$

$7+2+9\left( 4+6 \right)+2$

Add the numbers

$7+2+9 \times 10+2$

Multiply the numbers

$7+2+90+2$

Calculate the sum of the positive numbers

$101$

42/6+2+45/5*(32/8+3*2)+2