A garden store has the following miscellaneous flower bulbs in a basket:6 amaryllis5 daffodils3 lilies4 tulipsA customer bought 4 bulbs from the basket, one of each type of flower. If the next customer selects 1 of the remaining bulbs at random, which is closest to the probability that customer will get a "lily" bulb? A:36%B:29%C:17%D:14%

Answer:D. 14%.Step-by-step explanation:We have been given that a garden store has 6 amaryllis , 5 daffodils , 3 lilies  and 4 tulips flower bulbs in a basket.Since a customer had bought one of each type of flower bulb, so the number of remaining flower bulbs will be:5 amaryllis , 4 daffodils ,  2 lilies ,  3 tulips[tex]\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}[/tex][tex]\text{Probability of getting a lily bulb}=\frac{\text{Number of lily bulbs}}{\text{All bulbs}}[/tex][tex]\text{Probability of getting a lily bulb}=\frac{2}{5+4+2+3}[/tex][tex]\text{Probability of getting a lily bulb}=\frac{2}{14}[/tex][tex]\text{Probability of getting a lily bulb}=0.142857[/tex]Let us convert our answer into percentage by multiplying 0.142857 by 100.[tex]\text{Probability of getting a lily bulb}=0.142857\times 100[/tex][tex]\text{Probability of getting a lily bulb}=14.2857\%\approx 14\%[/tex]Therefore, the probability that the next customer will get a "lily" bulb is approximately 14% and option D is the correct choice.