A pennant is shaped like a right triangle, with hypotenuse 10 feet. the length of one side of the pennant is two feet longer than the length of the other side. find the length of the two sides of the pennant.

Let the shorter side be x
The other side is x + 2

a² + b² = c²
x² + (x + 2)² = 10²
x² + x² + 4x + 4 = 100
2x² + 4x - 96 = 0
x² + 2x - 48 = 0
(x+8)(x-6) = 0  
 x = - 8 (rejected, length cannot be negative), x = 6

x = 6
x + 2 = 6 + 2 = 8

Answer: The length are 6 ft and 8 ft