Q:

chelsea has $45 to spend at the fair. she spends $20. on admissib and $15 on snacks. she wants to play a game that costs $0.65 per game. Write an inequality to find the maximum number of times, x, Chelsa can play games. Using this inequality, determine the maximum number of times she can play the game.

Accepted Solution

A:
20 + 15 + 0.65x < = 45
35 + 0.65x < = 45
0.65x < = 45 - 35
0.65x < = 10
x < = 10 / 0.65
x < = 15.3......so the greatest number of games she can play is 15