consider the following systems of linear inequalities. x+2y>103x-4y>12which of the following ordered pairs are solutions to the system

Answer:(7,2)Step-by-step explanation:1. Firstly let's work with equalities respecting the conditions for these inequalities:[tex]\left\{\begin{matrix}x+2y>10 & \\ 3x-4y>12 & \end{matrix}\right.[/tex]So let's pick two values for the first and the second equation greater than 10, and than 12.Let's use the Addition Method, multiplying the [tex]\left\{\begin{matrix}x+2y=11 & \\ 3x-4y=13 & \end{matrix}\right.[/tex][tex]\left\{\begin{matrix}x+2y=11 & *(2)\\3x-4y=13 & \end{matrix}\right.\\\left\{\begin{matrix}2x+4y=22 & \\ 3x-4y=13 & \end{matrix}\right.\\5x=35\\x=7\\\\x+2y=11\\(7)+2y=11\\2y=4\\y=2[/tex]So, in this question there is not a list of options, but one of the possible pair is (7,2) the darker area below.