Ellen wishes to mix candy worth​ $1.45 per pound with candy worth​ $3.74 per pound to form 27 pounds of a mixture worth​$3.06 per pound. How many pounds of the more expensive candy should she​ use?r.

Let x pounds of candy worth $1.45 per pound are used.So price of x pounds = 1.45x.............(1)Total mixture is of 27 pounds , so for other candy it will be (27-x) poundsLet (27-x) pounds of candy worth $3.74 per pound are used.So price of (27-x) pounds = 3.74(27-x)............(2)Quantity of total mixture =27 poundsprice of one pound of mixture = $3.06Price of 27 pounds of mixture = 3.06 *27 = $82.62........(3)Price of mixture = Price of first type + price of second typeUsing (1) (2) and (3)[tex] 1.45x + (27-x) 3.74 = 82.62 [/tex]Now let us calculate x from here,x=8.02 Now the expensive candy quantity is (27-x) poundsSo quantity of expensive candy = (27-8.02) = 18.98 pounds.