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F(x) = -1/3(x+1)^2+4 How to find zeros ?
5 months ago
Q:
F(x) = -1/3(x+1)^2+4 How to find zeros ?
Accepted Solution
A:
$-\frac{1}{3}(x+2)^{2}=-4$
$(x+2)^{2}=12$
$x=2\sqrt{3}-2,x=-2\sqrt{3}-2$