Find the equation of a line parallel to y - 5x = 10 that passes through the point (3, 10). (answer in slope-intercept form)A) y = 5x - 5 B) y = 5x + 5 C) y = -5x - 5 D) y = 15x - 5

so, a line parallel to y - 5x = 10, will have the same slope as that equation, so what is that slope anyway?  let's solve for "y".

[tex]\bf y-5x=10\implies y=5x+10\implies y=\stackrel{slope}{5}x\stackrel{y-intercept}{+10}[/tex]

alrite, so the slope is 5 then, well, then the parallel line will have the same slope.

so, we're really looking for the equation of a line whose slope is 5 and runs through 3,10.


[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 3}}\quad ,&{{ 10}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 5 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-10=5(x-3) \\\\\\ y-10=5x-15\implies y=5x-5[/tex]