Given a cylinder with a diameter of 23 mm and a volume of 12464.27 mm3, find the area of the vertical cross-section that goes through the center of the bases. A. 172.5 mm3 B. 345 mm3 C. 690 mm3 D. 30 mm3
Accepted Solution
A:
Cylinder Volume = ¼ • π • d² • height
12,464.27 = .25 * PI * 23^2 * height
height = 12,464.27 / .25 * PI * 23^2
height = 12,464.27 / .25 * PI * 529
height = 12,464.27 / 415.4756284373
height = 30 mm
The vertical cross-section would be 23 mm * 30 mm = 690 SQUARE millimeters (NOT cubed as the answer says). answer is C