Given: segment AB || segment DE, C is the midpoint of segment DB. Prove: ΔACB ≅ ΔECD Fill in the missing reason for the proof. A) definition of midpoint B) vertical angles are congruent C) all right angles are congruent D) supplementary angles are congruent
Accepted Solution
A:
Answer:Given: Segment AB || segment DE, C is the midpoint of segment DB.Prove: ΔA CB ≅ ΔE CDProof: In ΔA CB and ΔE CD C is the Mid point of B D.BC=C D→ definition of midpoint∠A CB= ∠ EC D→→vertical angles are congruent∠BAC=∠DEC→→[AB║DE,so alternate angles are equal]→→ΔA CB ≅ ΔE CD[A AS or A SA]Option B: vertical angles are congruent