If w'(t) is the rate of growth of a child in pounds per year, what does 8 w'(t)dt 4 represent? The change in the child's weight (in pounds) between the ages of 4 and 8. The child's weight at age 4. The change in the child's age (in years) between the ages of 4 and 8. The child's weight at age 8. The child's initial weight at birth.

Answer:Option 1Step-by-step explanation:Her I attach a draw of the resolution to guide this explanation.We have to solve the integral 8 w'(t)dt 4. To solve it we need a primitive of w'(t), this is, a function that when derived gives us w'(t). This is the function w(t) that is the weight of the child in year t. So, to solve it we need to evaluate the primitive w(t) in the tract 4-8:8 w'(t)dt 4 = w(8) - w(4)As w(8) is the weight in year 8 and w(4) is the weight in year 4. This way, w(8)-w(4) is the difference in weights between 8 years and 4 years.This is the option 1: The change in the child's weight (in pounds) between the ages of 4 and 8.