John wants to know the volume of his gold ring in cubic centimeters. He gets a glass in the shape of a rectangular prism with a base 3\text{ cm}3 cm3, space, c, m by 2\text{ cm}2 cm2, space, c, m and fills the glass with 3.1\text{ cm}3.1 cm3, point, 1, space, c, m of water. John drops his gold ring in the glass and measures the new height of the water to be 3.7\text{ cm}3.7 cm3, point, 7, space, c, m. What is the volume of John's ring in cubic centimeters?

For this case the first thing to do is find the volume of the rectangular prism without the ring.
 We have then:
 [tex]v1 = (3) * (2) * (3.1) v1 = 18.6 cm ^ 3[/tex]
 We now look for the volume of the rectangular prism with the ring:
 [tex]v1 = (3) * (2) * (3.7) v2 = 22.2 cm ^ 3[/tex]
 Then, the volume of the ring will be the difference in volumes.
 We have then:
 [tex]v = v2 - v1 v = 22.2 - 18.6 v = 3.6 cm ^ 3[/tex]
 Answer:
 The volume of John's ring in cubic centimeters is:
 [tex]v = 3.6 cm ^ 3[/tex]