Ninety-three passengers rode in a train from City A to City B. Tickets for regular coach seats cost $122. Tickets for sleeper cars seats cost $284 The receipts for the trip totaled $18,960. How many passengers purchased each type of ticket?The number of coach tickets purchased was ____The number of sleeper car tickets purchased was ______
Accepted Solution
A:
Answer: number of coach tickets = 46 tickets number of sleeper car tickets = 47 tickets
Explanation: Assume that number of coach tickets is x and that number of sleeper car tickets is y
We are given that: 1- Total number of tickets purchased is 93. This means that: x + y = 93 This can be rewritten as: x = 93 - y ............> equation I 2- coach ticket costs $122, sleeper car ticket costs $284 and that the total receipt was for $18960. This means that: 122x + 284y = 18960 ..........> equation II
Substitute with I in II and solve for y as follows: 122x + 284y = 18960 122(93-y) + 284y = 18960 11346 - 122y + 284y = 18960 162y = 7614 y = 7614 / 162 y = 47
Substitute with y in equation I to get x as follows: x = 03 - y x = 93 - 47 x = 46