Simplify: Negative two and one-third minus negative ten and one-sixth a Negative twelve and one-half b Twelve and one-half c Seven and five-sixths d Negative seven and five-sixths Determine the answer to (−3) + (−5) and explain the steps using a number line. please give example and how you did itUse absolute value to express the distance between −12 and −15 on the number line.a |−12 − (−15)| = −27b |−12 − (−15)| = −3 c |−12 − (−15)| = 3d |−12 − (−15)| = 27please help im failing and its stressing

Answer:[tex]1.\rightarrow -2 \frac{1}{3}-(-10) \frac{1}{6}\\\\\rightarrow \frac{-7}{3} -\frac{-61}{6}\\\\\rightarrow \frac{-14+61}{6}\\\\\rightarrow \frac{47}{6}\\\\\rightarrow 7\frac{5}{6}[/tex]Option C→Seven and five-sixths 2.(-3) +(-5)Mark -3 and -5 on the number line.Move 5 units left of -3 to reach at -8.That is required sum.3.Distance between −12 and −15 on the number line is given by        |-12 -(-15}| or |-15 -(-12)|=|-12+15| or |-15+12|=|3| or |-3|=3 unitsOption C |−12 − (−15)| = 3