Solve 15 ≥ -3x or 2/5x ≥ -2. A.) {x | x ≤ -5}B.) {x | x ≥ -5}C.) {all reals}

[tex]15 \geq -3x\quad|:(-3)\qquad\vee\qquad \dfrac{2}{5}x \geq -2\quad|\cdot5\\\\\\ -5 \leq x\qquad\vee\qquad 2x \geq -10\quad|:2\\\\\\ -5 \leq x\qquad\vee\qquad x \geq -5\\\\\\x\geq -5\qquad\implies\qquad\boxed{\{x | x \geq -5\}}[/tex]

Answer B.