Suppose that a travel bureau claims that the trees in a forest are 85 feet tall on average, with a standard deviation of 0.2 feet. If you took a sample of 64 trees, which of the following mean heights would be outside the 95% confidence interval?

Answer:Step-by-step explanation:It is given that Suppose that a travel bureau claims that the trees in a forest are 85 feet tall on average, with a standard deviation of 0.2 feet.Here, Mean=85, Standard deviation=0.2, Sample=64.Now, using the confidence interval as 95%, then z=1.96.Thus, Margin error is given as:[tex]ME=\frac{1.96{\times}0.2}{\sqrt{64}}=\frac{0.392}{8}[/tex][tex]ME=0.049[/tex]Therefore, confidence interval: [tex]85-0.048<{\mu}<85+0.049[/tex]that is: [tex]84.95<{\mu}<85.049[/tex]Mean heights outside the confidence interval will be:[tex]x\leq84.95[/tex] and [tex]x\geq85.049[/tex].