The figure consists of two quarter circles and a square. What is the perimeter of this figure? Use 3.14 for π . 82.24 in. 114.24 in. 132.48 in. 164.48 in. (A square with sides measuring 16 in and has two quarter circles attached with with the same measurements.)

Answer:The perimeter of the figure is [tex]114.24\ in[/tex]Step-by-step explanation:we know thatThe perimeter of the figure is equivalent to the perimeter of a square plus the perimeter of a semicirclestep 1Find the perimeter of squareThe perimeter of square is equal to[tex]P=4b[/tex]whereb is the length side of the squarewe have[tex]b=16\ in[/tex]substitute[tex]P=4(16)=64\ in[/tex]step 2Find the circumference of a semicircleThe circumference of a semicircle is equal to[tex]C=\pi r[/tex]we have[tex]r=16\ in[/tex][tex]\pi=3.14[/tex]substitute[tex]C=3.14(16)=50.24\ in[/tex]step 3Find the perimeter of the figure[tex]64\ in+50.24\ in=114.24\ in[/tex]