Answer: [tex]\frac{1}{3}[/tex]Explanation:let y = [tex]log_{8} (2)[/tex]whenever we transfer base from log from one side to other it will remain be base after shifting to the other side.Change log to exponent form [tex]\log_xm=n\\m =x^{n}[/tex]here we have n = y, m=2, x=8 by substituting the values we will get[tex]8^{y} = 2[/tex] (1)we can write 8 in power of 2 that is [tex]2^{3}[/tex]we will rewrite the above equation (1) as [tex]2^{3y} = 2[/tex]we can equate the power when base is same then we will get 3y = 1 then [tex]y=\frac{1}{3}[/tex]