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Use the Remainder Theorem to find the remainder: (–6x3 + 3x2 – 4) ÷ (2x – 3).23-17.5-4.4444444...-0....
4 months ago
Q:
Use the Remainder Theorem to find the remainder: (–6x3 + 3x2 – 4) ÷ (2x – 3).23-17.5-4.4444444...-0.8888888...
Accepted Solution
A:
we have that
(–6x³ + 3x² – 4) ÷ (2x – 3)
----------------------║--------------------------
+6x³+9x² -3x²+6x+9
---------------------
12x²-4
-------------------
-12x²+18x
-------------------
18x-4
-----------------
-18x+27
----------------
23-----------------> the remainder
the answer is 23