What is the equation of a line that passes through the point (9, −3) and is parallel to the line whose equation is 2x−3y=6 ?Enter your answer in the box

2x - 3y = 6
-3y = -2x + 6
y = 2/3x - 2....the slope here is 2/3. A parallel line will have the same slope

y = mx + b
slope(m) = 2/3
(9,-3)...x = 9 and y = -3
now we sub and find b, the y int
-3 = 2/3(9) + b
-3 = 6 + b
-3 - 6 = b
-9 = b

so ur parallel equation is : y = 2/3x - 9 <== or 2x -3y = 27