This a line/equation represented in the slope y-intercept form: [tex]y=mx+b[/tex]
1) Coordinates of a point in the line are shown by y and x. 2) The variable m represents the slope of the line. 3) The variable b represents the y-intercept (when the line hits the y-axis) of the line.
We only need 2 pieces of the information (listed above) in order to graph the line.
Using the information provided by the equation... [tex]y=3x-2[/tex] ...we can graph the line.
We know that the slope is 3 (also shown as [tex] \frac{3}{1} [/tex]) as m=3 We also know one of the coordinate points (0,-2) due to the y-intercept. Now, we can graph: 1) Plot your first coordinate point. 2) [tex]m= \frac{rise}{run}[/tex] [tex]m= \frac{3}{1} [/tex] Your next point would be 3 sqaures up and 1 square to the right (or 3 sqaures down and 1 square to the left; Doesn't really matter as: [tex] \frac{3}{1}= \frac{-3}{-1}[/tex] This would result in a second coordiante point of (1,1) Now that you have two points on the plane, you can use a ruler and pencil to connect the points, forming the line which represents the equation.