a rectangle has a length of x inches and a width 3 inches less than the length. if the dimensions were doubled , what would be the area of the new rectangle in terms of x ?
Accepted Solution
A:
original length: x original width; x-3 original area: x(x-3) when the dimensions doubles, that is, increase by a factor of 2, the area increase by 2² 4[x(x-3)] 4x(x-3)=4x²-12x
you can also do it this way: original length: x doubled: 2x original width; x-3 doubled: 2(x-3) new area: 2x[2(x-3)]= 4x²-12x