MATH SOLVE

7 months ago

Q:
# Gerard bought 9 hamburgers and 3 orders of fries for 24.75. Chris bought 6 hamburgers and 4 orders of fries for 19.50. Each hamburger cost the same amount. Each Order of fries cost the same amount. Wrote a system of equations that can be used to find how much one hamburger and one Order of fries cost.

Accepted Solution

A:

9h + 3f = 24.75....multiply by 4

6h + 4f = 19.50 ...multiply by -3

----------------------

36h + 12f = 99 (result of multiplying by 4)

-18h - 12f = - 58.50 (result of multiplying by -3)

--------------------add

18h = 40.50

h = 40.50/18

h = 2.25Β <== hamburgers cost 2.25 each

6h + 4f = 19.50

6(2.25) + 4f = 19.50

13.50 + 4f = 19.50

4f = 19.50 - 13.50

4f = 6

f = 6/4

f = 1.50 <== fries cost 1.50 per order

6h + 4f = 19.50 ...multiply by -3

----------------------

36h + 12f = 99 (result of multiplying by 4)

-18h - 12f = - 58.50 (result of multiplying by -3)

--------------------add

18h = 40.50

h = 40.50/18

h = 2.25Β <== hamburgers cost 2.25 each

6h + 4f = 19.50

6(2.25) + 4f = 19.50

13.50 + 4f = 19.50

4f = 19.50 - 13.50

4f = 6

f = 6/4

f = 1.50 <== fries cost 1.50 per order