MATH SOLVE

7 months ago

Q:
# please help asapWhich table shows the first four terms of the sequence described by :f(x)= 4(2)^xx f(x)1 8 2 163 324 64x f(x)1 82 643 5124 4069x f(x)1 42 83 164 32x f(x)1 42 63 84 10

Accepted Solution

A:

We have the following function:

f (x) = 4 (2) ^ x

Evaluating we have:

For x = 1

f (1) = 4 (2) ^ 1 = 4 * 2 = 8

For x = 2

f (2) = 4 (2) ^ 2 = 4 * 4 = 16

For x = 3

f (3) = 4 (2) ^ 3 = 4 * 8 = 32

For x = 4

f (4) = 4 (2) ^ 4 = 4 * 2 = 64

Answer:

The correct table is:

x f(x)

1 8

2 16

3 32

4 64

f (x) = 4 (2) ^ x

Evaluating we have:

For x = 1

f (1) = 4 (2) ^ 1 = 4 * 2 = 8

For x = 2

f (2) = 4 (2) ^ 2 = 4 * 4 = 16

For x = 3

f (3) = 4 (2) ^ 3 = 4 * 8 = 32

For x = 4

f (4) = 4 (2) ^ 4 = 4 * 2 = 64

Answer:

The correct table is:

x f(x)

1 8

2 16

3 32

4 64