please help asapWhich table shows the first four terms of the sequence described by :f(x)= 4(2)^xx f(x)1 8 2 163 324 64x f(x)1 82 643 5124 4069x f(x)1 42 83 164 32x f(x)1 42 63 84 10
Accepted Solution
A:
We have the following function: f (x) = 4 (2) ^ x Evaluating we have: For x = 1 f (1) = 4 (2) ^ 1 = 4 * 2 = 8 For x = 2 f (2) = 4 (2) ^ 2 = 4 * 4 = 16 For x = 3 f (3) = 4 (2) ^ 3 = 4 * 8 = 32 For x = 4 f (4) = 4 (2) ^ 4 = 4 * 2 = 64
Answer: The correct table is: x f(x) 1 8 2 16 3 32 4 64