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Geometric sequence find the 16th term of - 3,6,-12
10 months ago
Q:
Geometric sequence find the 16th term of - 3,6,-12
Accepted Solution
A:
Here, first term (a) = -3 Geometric ratio (r) = 6/(-3) = -2 So 16 th term of Geometric series = ar^15 = -3(-2)^15 = 98,304