MATH SOLVE

7 months ago

Q:
# A mason needs to build a wall of 12mx4mx10cm. If the mixture that goes between the bricks occupies 12% of the volume of the wall, how many 20cmx10cmx5cm bricks will be needed?

Accepted Solution

A:

Bricks =1200Γ400Γ10Γ.88Γ·(20Γ10Γ5)
Bricks=42240