MATH SOLVE

9 months ago

Q:
# What is the equation of the line that is parallel to the givenline and passes through the point (-2, 2)?y=1/5x+4y=1/5x+12/5y=-5x+4y=-5x + 12

Accepted Solution

A:

Answer:[tex]y = \frac{1}{5} x + \frac{12}{5}[/tex]Step-by-step explanation:(-2,2) is a point on the graph of the required straight line. Now, we have four options of straight line and we have to choose from them which straight line is satisfied by the point (-2,2).
Now, [tex]y = \frac{1}{5} x + 4[/tex] line does not satisfy (-2,2) point.
Equation [tex]y = \frac{1}{5} x + \frac{12}{5}[/tex] does satisfy the point (-2,2).
Now, equation y = - 5x + 4 does not satisfy the point (-2,2).
Again, equation y = - 5x + 12 also does not satisfy the point (-2,2).
Therefore, the required equation is [tex]y = \frac{1}{5} x + \frac{12}{5}[/tex] (answer)