The 12500g iron bar at 20°C was supplied at 5000cal. Determine the temperature to which this bar was heated?

To solve this problem, we can use the heat equation: Q = mcΔT Where: Q = Heat energy absorbed (in calories) m = Mass of the object (in grams) c = Specific heat capacity of the material (in cal/g°C) ΔT = Change in temperature (final temperature - initial temperature) (in °C) Given: m = 12500 g (mass of the iron bar) c = Specific heat capacity of iron ≈ 0.11 cal/g°C (approximately) Q = 5000 cal (heat energy absorbed) We want to find the final temperature (Tf) of the iron bar. Rearranging the equation: ΔT = Q / (mc) Substitute the values: ΔT = 5000 cal / (12500 g * 0.11 cal/g°C) ΔT ≈ 0.3636°C Now, we can find the final temperature (Tf) by adding the change in temperature (ΔT) to the initial temperature (20°C): Tf = 20°C + 0.3636°C Tf ≈ 20.3636°C So, the temperature to which the iron bar was heated is approximately 20.36°C.