Find the difference of functions s and r shown below. r(x) = –x² + 3x s(x) = 2x + 1 (s – r)(x) =-x^2+3x-2x+1(-x^2+3x)-2x+1(2x+1)-(x^2 + 3x)2x+1-x^2+3x

Answer: (2x + 1) - (–x² + 3x) is difference .Step-by-step explanation:Given : r(x) = –x² + 3x  and  s(x) = 2x + 1To find : Find the difference of functions s and r .Solution :  We have given that  r(x) = –x² + 3x and s(x) = 2x + 1.Difference :(s – r)(x) = s(x) - r(x)               =(2x + 1) - (–x² + 3x)               = 2x +1 + x²-3x              = x²-x +1.Therefore, (2x + 1) - (–x² + 3x) is difference .