Find three positive consecutive integers such that the product of the second integer and the third integer is 72

Let
x---------> first  positive integer
x+1------> second positive integer
x+2-----> third positive integer

we know that
(x+1)*(x+2)=72-------> x² +2x+x+2=72 -------> x² +3x-70=0

using a graph tool-------> I solve the quadratic equation
see the attached figure

the roots are
x1=-10
x2=7

the answer is
first  positive integer is x=7
second positive integer is x+1=8
third positive integer is x+2=9