Select the system of linear inequalities whose solution is graphed. Coordinate plane with a system of two linear inequalities. The first is a solid line graphed with a slope of negative one, y-intercept of negative 2, and the region containing the origin is shaded. The second is a dashed vertical line 3 units to the left of the origin, and the region containing the origin is shaded. x ≥ –3; y ≥ x – 2x > –3; 5y ≥ –4x – 10x > –3; y ≥ –x + 1x > –2; y ≥ –x – 1
Accepted Solution
A:
Answer:[tex]x>-3 and y\geq -x-2[/tex]Step-by-step explanation:The first line has "equal to" because it is solid. It follows the same form as [tex]y\geq mx+b[/tex]where m is the slope which is -1 and b is the y-intercept which is -2.This means the equation is [tex]y\geq -x-2[/tex].The second line is 3 units to the left of the origin and is dashed so is [tex]x<a[/tex] or [tex]x>a[/tex]. Since it is 3 units and is including the origin (numbers greater than) then the line is [tex]x>-3[/tex]