The bulls eye on an archery target has a radius of 3 inches. the entire target has a radius of 9 inches. to the nearest tenth, find the area of the target outside of the bulls eye.
Accepted Solution
A:
Area of a circle = πr²
-------------------------------------------------------- Area of the archery target : -------------------------------------------------------- Area of the archery target = 9²π
Area of the archery target = 81π
-------------------------------------------------------- Area of the bull's eye : -------------------------------------------------------- Area of the bull's eye = 3²π
Area of the bull's eye = 9π
-------------------------------------------------------- Area outside the bull's eye : -------------------------------------------------------- Area of the target outside the bull's eye = 81π - 9π
Area of the target outside the bullseye =72π or 226.19 in²