The heights of adult men in america are normally distributed, with a mean of 69.1 inches and standard deviation of 2.65 inches. what percentage of adult males in america are under 5 feet 7 inches tall? round your answer as a percentage to the nearest whole number.
Accepted Solution
A:
The solution for this problem is:It's given that the heights are normally distributed. 5 feet 7 inches = (5*12 +7) inches = (60+7) inches = 67 inches. The z-score is (67 - 69.1)/(2.65) = -1.136. The probability is 0.127978 or 12.8%, making probability of a height over 67 inches