What is the length of JK, to the nearest tenth of a millimeter?
Accepted Solution
A:
5 = side a 3 = side c angle B = 62 degrees JK is side b Use the Law of Cosines to find the length of side b. b^2 = a^2 + c^2 − 2ac cos(B) b^2 = (5^2 + 3^2) − ( 2 x 5 x 3) cos(62°) b^2 = (25 + 9) − 30 x 0.469 b^2 = 34 - 30 x 0.469 b^2 = 34 - 14.084 b^2 = 19.916 b = √19.916 b = 4.463 Rounded to the nearest tenth is 4.5 mm.