the probability of winning a certain lottery is 1/77076 for people who play 908 times find the mean number of winsA) 0.0011B) 84.9C) 0.0118D) 0.000013

The mean is 0.0118 approximately. So option C is correctSolution:Given that , The probability of winning a certain lottery is [tex]\frac{1}{77076}[/tex] for people who play 908 timesWe have to find the mean number of wins[tex]\text { The probability of winning a lottery }=\frac{1}{77076}[/tex]Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial. [tex]n=908, \text { probability } \mathrm{p}=\frac{1}{77076}[/tex][tex]\text { Then, binomial mean }=n \times p[/tex][tex]\begin{array}{l}{\mu=908 \times \frac{1}{77076}} \\\\ {\mu=\frac{908}{77076}} \\\\ {\mu=0.01178}\end{array}[/tex]Hence, the mean is 0.0118 approximately. So option C is correct.